EL's+Earthquake+1+on+Oct+2005

EL's Earthquake data 2 on Oct 10 2005 near Indonesia

EL's Earthquake data 3 on Oct 19 2005 near Japan

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According to the picture in powerpoint, the estimated arrival time of earthquake wave to Hanford Observatory center is approximately 04:20:00 AM GMT. Since the meaured time of earthquake detected in a local area is 03:50:41AM GMT, I can imply that it takes about 29 minutes and 19 seconds.

- **P-Waves** are compressional waves, particles travel along the path of propagation. - **S-Waves** are shear waves, particles travel perpendicular to the direction of propagation. - Both P and S waves have own speeds because of different reaching time on the graph. 1. Distance from Hanford observatory center to the local earthquake in Pakistan : 10,459.46 km 2. Time taken to travel : 14 minutes and 19 seconds. 3. 5km/sec -> the speed of P-wave, 3km/sec -> the speed of S-wave
 * We can estimate P-wave is recorded through seismic y, S-wave is recorded through seismic x. It conveys that P-wave is faster than S-wave and does not oscillate vertically like S-wave does. We can see 2 relative maxima on seismic z graph while only 1 maximum appears on seismic x and y graph.
 * **Given**


 * **Procedure**

1. Divide the distance by the speed of P-wave to get how long does P-wave take to travel from Hanford Observatory center to local area. 10,559.46 km / (5km/sec) = 2111.892sec 1 minutes = 60 seconds 2111.892/ 60 = 35 minutes 19 seconds

2. Divide the distance by the speed of S-wave to get how long does S-wave take to travel from Hanford Observatory center to local area. 10,559.46 km/ (3km/sec) = 3519.82 sec 1 minutes = 60 secs 3519.82/ 60 = 58 minutes 6 seconds


 * **Conclustion**